F(x+3)=x^2+5

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Solution for F(x+3)=x^2+5 equation: 



(F+3)=F^2+5

We move all terms to the left:

(F+3)-(F^2+5)=0

We get rid of parentheses

-F^2+F+3-5=0

We add all the numbers together, and all the variables

-1F^2+F-2=0

a = -1; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·(-1)·(-2)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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